5*25^2x+3=(1/125)^1-x

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Solution for 5*25^2x+3=(1/125)^1-x equation: 



5*25^2x+3=(1/125)^1-x

We move all terms to the left:

5*25^2x+3-((1/125)^1-x)=0



Domain of the equation: 125)^1-x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

5*25^2x-((+1/125)^1-x)+3=0

Wy multiply elements

125x^2-((+1/125)^1-x)+3=0

We multiply all the terms by the denominator


125x^2*125)^1-x)-((+3*125)^1-x)+1=0

We add all the numbers together, and all the variables

125x^2*125)^1-x)-(375^1-x)+1=0

Wy multiply elements

15625x^3=0

We do not support expression: x^3

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